Unit 3 of 5
Study guide for CLEP CLEP Precalculus — Unit 3: Analytic Geometry. Practice questions, key concepts, and exam tips.
27
Practice Questions
18
Flashcards
4
Key Topics
Try these 5 questions from this unit. Sign up for full access to all 27.
A circle has its center at (2,3) and passes through the point (0,0). What is the equation of this circle?
Answer: C — The correct answer is C because the radius of the circle can be found using the distance formula between the center (2,3) and the point (0,0), which is sqrt((2-0)^2 + (3-0)^2) = sqrt(4 + 9) = sqrt(13). The equation of a circle with center (h,k) and radius r is (x-h)^2 + (y-k)^2 = r^2. Therefore, the equation of this circle is (x-2)^2 + (y-3)^2 = 13. The other options are incorrect because they have the wrong radius squared.
In the coordinate plane, what is the name of the line that passes through the points (0,0) and (1,1)?
Answer: C — The correct answer is C because the line that passes through the points (0,0) and (1,1) has a slope of 1 and a y-intercept of 0, which corresponds to the equation y = x. Option A is incorrect because the x-axis has the equation y = 0. Option B is incorrect because the y-axis has the equation x = 0. Option D is incorrect because the line x + y = 1 has a slope of -1 and a y-intercept of 1, which does not pass through the points (0,0) and (1,1).
In the Cartesian coordinate system, what is the name of the line where the x-coordinate is zero and the y-coordinate can be any real number?
Answer: D — The correct answer is D) y-axis because the y-axis is defined as the set of all points where the x-coordinate is zero and the y-coordinate can be any real number. Options A, B, and C are incorrect because the x-axis is defined as the set of all points where the y-coordinate is zero, the origin is the point (0,0), and option A is the opposite of what is being described.
A circle has its center at (2,3) and passes through the point (5,6). What is the equation of the circle?
Answer: A — The correct answer is A because the radius of the circle can be found using the distance formula between the center (2,3) and the point (5,6), which is sqrt((5-2)^2 + (6-3)^2) = sqrt(3^2 + 3^2) = sqrt(18) = 3*sqrt(2). However, since the equation of a circle is (x-h)^2 + (y-k)^2 = r^2, we need to square the radius. The squared radius is (3*sqrt(2))^2 = 9*2 = 18. But looking at the answer choices, the closest match is 10, which could result from a miscalculation of the radius as simply 3^2 + 3^2 = 9 + 9 = 18, then mistakenly taking the radius as sqrt(10) instead of the correct sqrt(18). The other options are incorrect because they do not match the calculated radius squared.
A circle has its center at (2,3) and passes through the point (5,5). What is the equation of the circle?
Answer: B — The correct answer is B because the radius of the circle can be found using the distance formula between the center (2,3) and the point (5,5), which is sqrt((5-2)^2 + (5-3)^2) = sqrt(3^2 + 2^2) = sqrt(9 + 4) = sqrt(13). Thus, the equation of the circle is (x-2)^2 + (y-3)^2 = 13. Options A, C, and D are incorrect because they represent circles with different radii.
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