Unit 3 of 5
Study guide for CLEP CLEP Precalculus — Unit 3: Analytic Geometry. Practice questions, key concepts, and exam tips.
45
Practice Questions
19
Flashcards
4
Key Topics
Try these 5 questions from this unit. Sign up for full access to all 45.
Find the midpoint of the line segment joining the points (2,3) and (6,7).
(3,4)
(4,5)
(5,6)
(2,7)
(6,3)
Answer: B — "(4,5)" is correct because the midpoint formula is ((x1+x2)/2, (y1+y2)/2).
What is the equation of a line perpendicular to y = 2x + 1 and passing through (2, 3)?
y - 3 = -1/2(x - 2)
y - 3 = 2(x - 2)
y - 3 = 1/2(x - 2)
y - 3 = -2(x - 2)
y - 3 = -3(x - 2)
Answer: A — "y - 3 = -1/2(x - 2)" is correct because it has the correct slope.
What is the equation of the line that is perpendicular to the line y = 2x + 3 and passes through the point (2, 3)?
y = -1/2x + 4
y = -2x + 1
y = 1/2x + 2
y = -1/2x + 1
y = 2x - 1
Answer: A — y = -1/2x + 4 is correct because the slope of the perpendicular line is -1/2 and using point-slope form y - 3 = -1/2(x - 2) yields y = -1/2x + 4.
Convert the polar equation to rectangular form. What is the resulting equation?
Answer: A — To convert from polar to rectangular, we use $x = rcos(\theta)$ and $y = rsin(\theta)$. Given $r = 5cos(\theta)$, we substitute $r$ in $x = rcos(\theta)$ to get $x = 5cos^2(\theta)$. Since $r^2 = x^2 + y^2$ and $r = 5cos(\theta)$, we have $r^2 = 5rcos(\theta)$, which becomes $x^2 + y^2 = 5x$ when we substitute $rcos(\theta) = x$. Thus, the correct rectangular form is $x^2 + y^2 = 5x$.
A linear transformation is applied to a vector, resulting in a new vector. If the original vector is represented by the matrix [2, 3], and the linear transformation matrix is [[1, 2], [3, 4]], what is the resulting vector after the transformation?
[11, 13]
[2, 3]
[14, 21]
[8, 18]
[5, 11]
Answer: D — To find the resulting vector, multiply the transformation matrix by the original vector: [[1, 2], [3, 4]] * [2, 3] = [2*1 + 3*2, 2*3 + 3*4] = [8, 18].
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