Unit 1 of 5
Study guide for CLEP CLEP Precalculus — Unit 1: Algebraic Expressions & Equations. Practice questions, key concepts, and exam tips.
159
Practice Questions
15
Flashcards
4
Key Topics
Try these 5 questions from this unit. Sign up for full access to all 159.
What is the focus of a parabola with equation x² = 20y?
(0,4)
(0,5)
(0,2)
(0,6)
(0,8)
Answer: B — (0,5) is correct because the standard equation of a parabola with vertex (0,0) and focus (0,p) is x² = 4py, and since x² = 20y, 4p = 20, so p = 20/4 = 5.
If sec(x) = 2, what is the value of cos(x)?
0.25
0.5
0.75
1
1.5
Answer: B — 0.5 is correct because sec(x) is the reciprocal of cos(x), so cos(x) = 1 / sec(x) = 1 / 2 = 0.5.
What is the tabular representation of the function f(x) = 3x - 2 for x-values -2, -1, 0, 1, 2?
x: -2, -1, 0, 1, 2; f(x): -2, 1, 4, 7, 10
x: -2, -1, 0, 1, 2; f(x): -6, -3, 0, 3, 6
x: -2, -1, 0, 1, 2; f(x): -4, -1, 2, 5, 8
x: -2, -1, 0, 1, 2; f(x): -8, -5, -2, 1, 4
x: -2, -1, 0, 1, 2; f(x): 0, 3, 6, 9, 12
Answer: D — x: -2, -1, 0, 1, 2; f(x): -8, -5, -2, 1, 4 is correct because the function f(x) = 3x - 2 is evaluated at each x-value to obtain the corresponding f(x) values, resulting in the given table.
If h(x) = |x| + 2, what is h(-5)?
3
5
7
9
11
Answer: C — 7 is correct because since h(x) = |x| + 2, then h(-5) = |-5| + 2 = 5 + 2 = 7.
If f(x) = 2x + 1, what is the value of f(-3)?
-5
-4
-3
-2
-1
Answer: A — -5 is correct because substituting -3 into the equation f(x) = 2x + 1 gives f(-3) = 2(-3) + 1 = -6 + 1 = -5.
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