CLEP College Algebra Practice Test

10 free sample questions with answers and explanations. See how you'd score on the real CLEP exam.

Question 1Unit 1: Algebraic Foundations

What is the value of the expression 3 + 2 × 5 - 1?

A
A) 10
B
B) 12
C
D) 16
D
C) 14

Explanation

To evaluate the expression 3 + 2 × 5 - 1, we must follow the order of operations (PEMDAS): Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). Since there are no parentheses or exponents, we start with multiplication: 2 × 5 = 10. Then, we perform addition and subtraction from left to right: 3 + 10 = 13, and 13 - 1 = 12. However, the correct sequence is 3 + 10 = 13 and then 13 - 1 = 12, but considering the options and reevaluating, the mistake was in the final step explanation. The correct step-by-step evaluation should be: 2 × 5 = 10, then 3 + 10 = 13, and finally 13 - 1 = 12. This matches option B, not C, upon reevaluation. The mistake in the initial explanation was suggesting the final answer was 14, which does not align with any step provided. The correct calculation following PEMDAS is indeed 3 + (2 × 5) - 1 = 3 + 10 - 1 = 12, which means the initial explanation mistakenly identified the correct answer as C) 14 instead of B) 12. The correct answer, following the accurate application of PEMDAS and the provided options, should indeed reflect the result of the expression 3 + 2 × 5 - 1, which is 12.

Question 2Unit 1: Algebraic Foundations

What is the value of the expression 18 ÷ 3 + 12 - 8 ÷ 2?

A
C) 14
B
B) 12
C
D) 16
D
A) 10

Explanation

To evaluate this expression, we need to follow the order of operations (PEMDAS): Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). First, we perform the division operations: 18 ÷ 3 = 6 and 8 ÷ 2 = 4. Then, we perform the addition and subtraction operations from left to right: 6 + 12 = 18 and 18 - 4 = 14. Therefore, the correct answer is 14. This question tests the student's ability to apply the order of operations to evaluate an expression with multiple operations. The distractors target common misconceptions such as forgetting to follow the order of operations or performing operations out of order.

Question 3Unit 1: Algebraic Foundations

What is the value of the expression 3 × 2 + 12 ÷ 4?

A
A) 7
B
B) 9
C
D) 15
D
C) 11

Explanation

To evaluate the expression 3 × 2 + 12 ÷ 4, we need to follow the order of operations (PEMDAS): Parentheses, Exponents, Multiplication and Division (from left to right), and Addition and Subtraction (from left to right). First, we perform the multiplication: 3 × 2 = 6. Then, we perform the division: 12 ÷ 4 = 3. Finally, we add the results: 6 + 3 = 9. Therefore, the correct answer is B) 9. The incorrect options are: A) 7 (forgetting to follow the order of operations), C) 11 (incorrectly adding before multiplying), and D) 15 (incorrectly multiplying before dividing).

Question 4Unit 4: Polynomial and Rational Functions

What is the result of dividing the polynomial x^3 - 6x^2 + 11x - 6 by the polynomial x - 2?

A
A) x^2 - 4x + 3
B
D) x^2 + 4x - 3
C
C) x^2 + 4x + 3
D
B) x^2 - 4x - 3

Explanation

To divide the polynomial x^3 - 6x^2 + 11x - 6 by the polynomial x - 2, we can use polynomial long division or synthetic division. By applying the polynomial division algorithm, we first divide the leading term of the dividend (x^3) by the leading term of the divisor (x), which gives x^2. Then we multiply the divisor (x - 2) by x^2, which gives x^3 - 2x^2. Subtracting this from the original polynomial gives -4x^2 + 11x - 6. Repeating the process, we divide -4x^2 by x, giving -4x. Multiplying the divisor (x - 2) by -4x gives -4x^2 + 8x. Subtracting this from -4x^2 + 11x - 6 gives 3x - 6. Finally, dividing 3x by x gives 3, and multiplying the divisor (x - 2) by 3 gives 3x - 6. This exactly matches the remaining polynomial, leaving no remainder. Thus, the quotient is x^2 - 4x + 3. This process applies the property of polynomial division, where the degree of the quotient is less than the degree of the divisor, and the remainder is either zero or of lesser degree than the divisor. The correct option, A) x^2 - 4x + 3, represents this quotient correctly. Distractor B applies a sign flip trap, C represents a related but different concept (adding instead of subtracting), and D applies a common misconception of ignoring the remainder or misapplying the division algorithm.

Question 5Unit 5: Exponential and Logarithmic Functions

A population of bacteria grows according to the function P(t) = 200e^(0.5t), where t is time in hours. How many bacteria will be present after 4 hours?

A
A) 800
B
B) 1200
C
C) 1600
D
D) 2000

Explanation

To find the number of bacteria after 4 hours, we can plug in t = 4 into the given function P(t) = 200e^(0.5t). Using the property of exponential functions, we get P(4) = 200e^(0.5*4) = 200e^2. Using a calculator, we find that e^2 ≈ 7.389, so P(4) = 200 * 7.389 ≈ 1478. However, among the given options, the closest value is 1600. This question requires the application of exponential growth functions to model real-world scenarios, which is a key concept in college algebra. The correct answer is C) 1600. Distractor A) 800 represents a common misconception of underestimating the growth rate, while B) 1200 and D) 2000 represent overestimations.

Question 6Unit 2: Equations and Inequalities

A student is solving the equation 2x + 5 = 11. Which of the following steps would the student take to isolate x?

A
C) Multiply both sides by 2 and then subtract 5
B
D) Divide both sides by 2 and then add 5
C
A) Subtract 5 from both sides and then divide by 2
D
B) Add 5 to both sides and then divide by 2

Explanation

To isolate x, we need to get x by itself on one side of the equation. The correct step is to subtract 5 from both sides of the equation 2x + 5 = 11, which results in 2x = 11 - 5, or 2x = 6. Then, we divide both sides by 2 to get x = 6 / 2, or x = 3. This is an application of the subtraction property of equality and the division property of equality. Option B is incorrect because adding 5 to both sides would increase the value of the left side, moving it further away from isolating x. Option C is incorrect because multiplying both sides by 2 would require us to also multiply the constant term by 2, not subtract it. Option D is incorrect because dividing both sides by 2 first would not allow us to eliminate the constant term +5.

Question 7Unit 3: Functions and Their Graphs

What is the domain of the function f(x) = (2x + 1) / (x^2 - 4)?

A
D) (-∞, -2) ∪ (-2, ∞)
B
C) (-∞, 2) ∪ (2, ∞)
C
A) (-∞, -2) ∪ (-2, 2) ∪ (2, ∞)
D
B) (-∞, -2) ∪ (2, ∞)

Explanation

To find the domain of the function f(x) = (2x + 1) / (x^2 - 4), we need to determine the values of x for which the denominator is not equal to zero. The denominator is a quadratic function, x^2 - 4, which can be factored as (x + 2)(x - 2). Therefore, the denominator is equal to zero when x = -2 or x = 2. The domain of the function is all real numbers except x = -2 and x = 2. Using interval notation, the domain can be written as (-∞, -2) ∪ (-2, 2) ∪ (2, ∞). This is because the function is undefined at x = -2 and x = 2, but is defined for all other real numbers. Distractor B is incorrect because it only excludes x = 2, but not x = -2. Distractor C is incorrect because it only excludes x = 2, but includes x = -2. Distractor D is incorrect because it includes x = -2, which is not in the domain of the function.

Question 8Unit 5: Exponential and Logarithmic Functions

Simplify the expression log₂(4x) using logarithm properties.

A
C) log₂(4) + log₂(x)
B
D) log₂(4) - log₂(x)
C
A) 2 + log₂(x)
D
B) 2log₂(x)

Explanation

To simplify the expression log₂(4x), we apply the product rule of logarithms, which states that logₐ(MN) = logₐ(M) + logₐ(N). In this case, M = 4 and N = x. Therefore, log₂(4x) = log₂(4) + log₂(x). This is because the logarithm of a product can be expressed as the sum of the logarithms. Option A is incorrect because it applies the sum rule incorrectly. Option B is incorrect because it applies the power rule of logarithms incorrectly. Option D is incorrect because it applies the quotient rule of logarithms incorrectly.

Question 9Unit 5: Exponential and Logarithmic Functions

Solve for x in the equation 2^x = 16

A
D) x = 5
B
C) x = 2
C
B) x = 4
D
A) x = 3

Explanation

To solve for x, we can use the property of exponents that states if a^x = a^y, then x = y. Since 16 can be written as 2^4, we have 2^x = 2^4. Therefore, x = 4. This is an application of the one-to-one property of exponential functions, which states that if f(x) = a^x, then f(x) is one-to-one if a is positive and not equal to 1. The correct answer is x = 4. Distractor A targets the misconception of not fully simplifying the equation, distractor C targets the misconception of incorrectly applying the property of exponents, and distractor D targets the misconception of adding an extra step to the solution.

Question 10Unit 5: Exponential and Logarithmic Functions

Solve for x in the equation ln(x) + ln(2x) = 3

A
A) x = 1/2
B
D) x = 2e^3
C
B) x = e^(3/2)
D
C) x = e^3 / 2

Explanation

To solve for x, we can use the property of natural logarithm that states ln(a) + ln(b) = ln(ab). Applying this property, we get ln(x) + ln(2x) = ln(2x^2). Since ln(2x^2) = 3, we can rewrite it as 2x^2 = e^3. Then, x^2 = e^3 / 2, and finally, x = sqrt(e^3 / 2) = e^(3/2). The correct answer is B) x = e^(3/2). Distractor A is incorrect because it forgets to apply the property of natural logarithm. Distractor C is incorrect because it incorrectly applies the property of natural logarithm. Distractor D is incorrect because it ignores the coefficient of x in the equation.

Want your full diagnostic with pass probability?

Get a personalized breakdown of every unit, estimated study time, and an AI study plan — free.