Unit 1 of 5
Study guide for CLEP CLEP Calculus — Unit 1: Limits and Continuity. Practice questions, key concepts, and exam tips.
339
Practice Questions
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Key Topics
Try these 5 questions from this unit. Sign up for full access to all 339.
If a function f(x) is differentiable at x = a, what can be concluded about its continuity at x = a?
Answer: B — It is continuous is correct because differentiability implies continuity, since the existence of a derivative at a point requires the function to have a well-defined limit at that point, which is the definition of continuity.
Find the slope of y = x^3 - 2x^2 + x - 1 at x = 3.
Answer: D — 16 is correct because the derivative of y = x^3 - 2x^2 + x - 1 is y' = 3x^2 - 4x + 1, and at x = 3, y' = 3*3^2 - 4*3 + 1 = 27 - 12 + 1 = 16.
Find the derivative of y = $tan^{2}$(x).
Answer: A — "2tan(x)$sec^{2}$(x)" is correct because chain rule applies.
Find the limit of the function f(x) = (e^x - 1) / x as x approaches 0 using L'Hospital's Rule.
Answer: A — Apply L'Hospital's Rule to find the limit. The derivative of the numerator is e^x, and the derivative of the denominator is 1. So, the limit is $e^{0}$ / 1 = 1.
Find the derivative of y = arctan(x^2).
Answer: A — 2x / (1 + x^4) is correct because the derivative of arctan(u) is given by 1 / (1 + u^2) and applying the chain rule with u = x^2 gives us 2x / (1 + (x^2)^2).
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